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⇒ P Lies On A Fixed Arc Through A, B Ab = Ac + ∠Bac = 90° Invites A 90° Rotation About A: B → C, P → P' △App' Is Iso Right ⇒ Pp' = √2·Pa, ∠Ap'p = 45° ∠Ap'c = ∠Apb = 105° (Rotation Preserves Angles) ⇒ ∠Pp'c = 105° − 45° = 60° Drop Ch ⊥ Pp': 30 60 90 + Pythagoras ⇒ Pc² = 2Pa² + Pb² − √2·Pa·pb Let X = Pb/Pa: Pc²/Pa² = (X − √2/2)² + 3/2 ≥ 3/2 (Perfect Square!) → Watch The Full Animation To See Each Construction Emerge Step By Step. T”. According to user @tiktok_jp_29: “I Was On A.
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